Quote:
Originally Posted by rjn5656
Looking to put a Mitsubishi Mitsubishi ceiling cassette in enclosed lanai in my Gardenia (10 x 28). One conractor recommended 1 ton unit, another 1.5 unit. Anyone with a Gardenia that has done it?
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It doesn't matter the model of home - it's how many square feet. You can find some good information on the internets. I found -
A common rule of thumb is to assume that a standard HVAC unit can cool around 400 square feet of residential space per ton of cooling capacity. When calculating the power you need to cool your home, you can assign 12,000BTUs that need to be cooled per 400 square feet of property. So determine the square feet of you area. If answer comes to over one ton, I would round up to 1.5 as I suspect the area may not be well insulated causing heat to build up more rapidly than in "regular" rooms. Also, I assume the calculation above is for a standard eight foot ceiling. I did not see any calculation for cooling needed for cubic feet which would have been more helpful.
Multiply your cubic foot measurement by 1,027 to convert to British thermal units. For example, a 50-cubic foot room multiplied by 1,027 equals 51,350 British thermal units.
Step 3
Divide your British thermal units number by 12,000 to convert to tons. For example, a room that requires 513,500 British thermal units per hour to cool would require a 4.3 ton air conditioning system.