Math Problem

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Old 12-07-2022, 07:31 AM
CoachKandSportsguy CoachKandSportsguy is offline
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Originally Posted by tuccillo View Post
I believe what you are looking for are the number of permutations. If that is the case, the number is 210 for the first category and 504 for the second category.
That's a total of 714 trophies, I should have been a trophy maker!

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Old 12-07-2022, 10:46 AM
fdpaq0580 fdpaq0580 is offline
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Originally Posted by Normal View Post
It’s a perm, because order does matter. Don’t treat it as a combination.
When awards are handed out, often they award 3rd place first, then second, then first.
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Old 12-08-2022, 05:42 AM
b0bd0herty b0bd0herty is offline
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Originally Posted by tuccillo View Post
I believe what you are looking for are the number of permutations. If that is the case, the number is 210 for the first category and 504 for the second category.
Actually, there are only 3 awards so THOSE 3 awards can only be present in 6 possible arrangements. That makes 6 and 6.
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Old 12-08-2022, 05:47 AM
b0bd0herty b0bd0herty is offline
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Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
Most critical question, in how many different ways could the 6 awards be presented?
Each of the categories has 3 awards and can't be combined with the other so, if one is being realistic, catagory one has 3 awards and catagory two has three awards.

3 (of anything) only has 6 possible arrangements so the answer would be:
6 different ways for each category or 12 different ways for thoses 6 awards.
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Old 12-08-2022, 06:53 AM
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Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
The performances were lousy. No awards given!
  #21  
Old 12-08-2022, 08:09 AM
Notsocrates Notsocrates is offline
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Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?

(7x6x5)+(6x5x4)= # of possibilities
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Old 12-08-2022, 08:26 AM
tuccillo tuccillo is offline
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The wording of the question could have been better. Regardless, I am pretty sure the intent was to compute the possible permutations, which was my answer. Otherwise, the number of participants in the two categories would not have been presented.


Quote:
Originally Posted by b0bd0herty View Post
Actually, there are only 3 awards so THOSE 3 awards can only be present in 6 possible arrangements. That makes 6 and 6.
  #23  
Old 12-08-2022, 08:41 AM
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Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
There are no 1rst, 2nd or 3rd place awards. Everybody gets a participation medal and complains that they had to practice too much.
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Old 12-08-2022, 08:42 AM
Whitley Whitley is offline
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Quote:
Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
There are so many ways this can be taken. Was permutation in the original question?

Last edited by Whitley; 12-08-2022 at 08:55 AM.
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Old 12-08-2022, 08:44 AM
Whitley Whitley is offline
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Originally Posted by Velvet View Post
I took the problem from a school math test. The question is looking for the total possibilities…( and that’s where I made a mistake when I tried it. )
I hate when questions are not clear. In college I would clarify the various ways the question could be perceived, then solve for each. Drove the profs crazy.
  #26  
Old 12-08-2022, 08:50 AM
Whitley Whitley is offline
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Originally Posted by Two Bills View Post
My grandson loves math.
I can't even understand any of the stuff he does.
Kids today are so far in front of where we were at same age.
I was a bit thick anyway, but I knew how to work out my hours and wages!
I was on the board of a few schools in NY. I felt they were going the wrong way as far as teaching math went. In grade school, instead of providing the actual answer, they were being asked to estimate the answer. There is no estimate in math. There is one correct answer.
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Old 12-08-2022, 08:52 AM
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Originally Posted by Steve View Post
There are no 1rst, 2nd or 3rd place awards. Everybody gets a participation medal and complains that they had to practice too much.
The act of holding the contest is triggering and a micro aggression. Shame on them.
  #28  
Old 12-08-2022, 09:01 AM
Rodneysblue Rodneysblue is offline
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Quote:
Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
————-—————42————————-

From Hitchhikers Guide to the Galaxy

Last edited by Rodneysblue; 12-08-2022 at 09:05 AM. Reason: Clarification
  #29  
Old 12-08-2022, 10:55 AM
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So, if people who play piano don’t also play the violin so they can’t get an award for playing the violin, and people who play violin don’t also play the piano, would the answer be (9X8x7) + (7x6x5)?
  #30  
Old 12-08-2022, 11:57 AM
rsimpson rsimpson is offline
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Quote:
Originally Posted by Velvet View Post
A music festival award gives awards for 1st, 2nd and 3rd place in each category. If there are 7 contestants for piano and 9 for violin, in how many different ways could the 6 awards be presented?
567 combinations. (3 x 7 x 3 x 9)
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